Question

Now we want to display which error was thrown in our voting program. ( BOTH QUESTIONS ARE PYTHONS PROGRAMS)

1. Add the appropriate code to the try/except statement so the exception is displayed.
2. Run the program and, when prompted, enter the word 'old' so your output matches the output under Desired Output.

# Set the variable
age = input("What is your age?")

# Insert a try/except statement
# here when you convert the input
# to a number using int()
try:
age = int(age)
if age >= 18:
print("Go vote!")
  
except:
print("Please enter a valid age!")

Output:

invalid literal for int() with base 10: 'old'
Please enter a valid age!

We're working with pie now. Our code is already catching when the user does not enter a valid integer, but we need to add default handling to catch everthing else.

1. Add the appropriate code to the try/except statement so that there is default handling for all other errors. It should display the statement "Something went wrong!"
2. Run the program and, when prompted, enter the number zero so your output matches the output under Desired Output.

# Get Input
pieces = input("How many pieces of pie do you want? ")

# Attempt to convert to integer
try:
percentage = 1/int(pieces)
except ValueError:
print("You need to enter a number!")
  

Output:

Something went wrong!

Answer 1

Answer:-

Your Code

Here is the same output that you want...

Output

When - Enter - 18

When Enter - Old

If you have any question feel free to ask....

Best of luck...