Question

Use python write a function that takes the scores of all players as keyword arguments and returns the name of the player with maximum score after calculating the scores with the truncated mean scoring(remove one highest score and one lowest score). Do not import anything

eg.

def bp(**player_scores):

    >>> bp(ab=[9.6, 9, 9.8, 9.9], bc=[9.0, 9.5, 9.9],cd=[10.0, 9.8, 10.0, 9.5, 9.6])

    'cd'

    >>> bp(ab=[3.8, 3.5, 3.2], bc=[4.0, 3.6, 3.0])

    'bc'

  

Answer 1

def bp(**player_scores):
    best_player = ''
    best_score = 0
    for player, scores in player_scores.items():
        total = 0
        smallest = None
        largest = None
        for score in scores:
            total += score
            if largest is None or score > largest:
                largest = score
            if smallest is None or score < smallest:
                smallest = score
        truncated_mean_score = (total - smallest - largest) / (len(scores) - 2)
        if truncated_mean_score > best_score:
            best_score = truncated_mean_score
            best_player = player
    return best_player


# Testing the function here. ignore/remove the code below if not required
print(bp(ab=[9.6, 9, 9.8, 9.9], bc=[9.0, 9.5, 9.9], cd=[10.0, 9.8, 10.0, 9.5, 9.6]))
print(bp(ab=[3.8, 3.5, 3.2], bc=[4.0, 3.6, 3.0]))