Question

1. Given PI on a roadway at 25 + 88.10, Δ = 10°10 (Delta angle)′, and D = 7°45'. "D" is the degree of curvature of the roadway.

The External distance (E) from the midpoint of the roadway curvature to the point of intersection of the tangents (roadways) PI is _______feet.

Your answer will be in feet to 4 place accuracy. X.XXXX

2.

Traverse leg AB has a length (distance) of 100' ( Point A is at the center of the cartesian system and B is at the end of the leg segment) and an azimuth of 258*47'12"

The bearing is  _____degrees .

Your answer for A is a quadrant direction, ie, N, E, S, W

Your answer B will be in decimal degrees to 4 place accuracy. XX.XXXX

You answer for C is a quadrant direction, ie, N, E, S, W

Answer 1

Sta PC = Sta PI - T = Sta (25+88.10) - 65.7640 = Sta (25+22..34)

Length of curve (L) = πR/180° = π*739.30*(10°10')/180° = 131.61 ft

Sta PT = Sta PC + L = Sta (25+22.34)+ 131.61 = Sta (26+53.95)