Question

A completely mixed activated-sludge process is being designed for a wastewater flow of (2.64 mgd) using the kinetics equations. The influent BOD of 120 mg/Lis essentially all soluble and the design effluent soluble BOD is 7 mg/L, which is based on a total effluent BOD of 20 mg/L. For sizing the aeration tank, the mean cell residence time is selected to be10 days and the MLVSS 2000 mg/L. The kinetic constants from a bench-scale treatability study are as follows: Y = 0.60 mg VSS/mg BOD, Kd= 0.06 day-1, Ks= 60 mg/Lof BOD, (K) or μmax= 5.0 day-1. Determine the BOD removal efficiency, F/M ratio, volume of the aeration tank, aeration time, concentration of substrate (BOD) in the effluent, and the sludge production rate.

Answer 1