Question

The semimajor axis and flattening for the ITRS ellipsoid are 6,378,138.149 m and 1/298.25646, respectively. What is the eccentricity of the ellipsoid? (nearest 0.00000001)

Answer 1

Given that

the semi major axis for ellipsoid (a)=6378138.149m

Flattening (f) = 1/298.25646

First eccentricity (e2) =2f-f2

e2=2(1/298.25646)-(1/298.25646)2

  e2=0.006694

e=0.0818168686763

Second eccentricity (e') =e/√(1-e2)

e'=0.0818168686763/√(1-0.08181686867632)

e'=0.082