Question

A 14 mgd wastewater treatment plant has a primary clarifier that treats an influent with 800...

A 14 mgd wastewater treatment plant has a primary clarifier that treats an influent with 800 mg/L of solids and a removal efficiency of 55%. Sludge at the bottom of the tank is pumped at a rate of 0.1 mgd.

a. What is the effluent solids concentration from the clarifier (in mg/L)?

b. What is the solids concentration in the sludge at the bottom of the tank (in mg/Land %)?

c. The primary sludge is further processed in a digester following treatment. What weight of solids (in lbs) need to be handled each week in the waste sludge?

Engineering   Civil-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The volumetric flow to the ACME wastewater treatment plant is 25 MGD. The influent soluble BOD5...
The volumetric flow to the ACME wastewater treatment plant is 25 MGD. The influent soluble BOD5 is 200 mg/L and the effluent soluble BOD5 is 8 mg/L. The plant is designed to operate with a mean cell (biomass) residence time of 10 days. The yield coefficient is 0.6 mg biomass/mg substrate, and the biomass decay rate is 0.09/day. The reactor is to operate at a biomass concentration of 2500 mg/L. The thickened underflow biomass concentration from the secondary clarifier is...
A wastewater treatment plant that treats wastewater to secondary treatment standards uses a primary sedimentation process...
A wastewater treatment plant that treats wastewater to secondary treatment standards uses a primary sedimentation process followed by an activated sludge process composed of aeration tanks and a secondary clarifiers. This problem focuses on the activated sludge process. The activated sludge process receives a flow of 15 million gallons per day (MGD). The primary sedimentation process effluent has a BOD5 concentration of 180 mgBOD5/L (this concentration is often referred as S). Before flowing into the activated sludge process, the primary...
Q3: A 500,000-gallon rectangular clarifier receive 7 millions gallons per day. The primary influent BOD concentration...
Q3: A 500,000-gallon rectangular clarifier receive 7 millions gallons per day. The primary influent BOD concentration is 300 mgBOD/L. The primary influent TSS concentration is 350 mg/L and the sludge production is 10,000 lbsTS/ day. a) What is the average primary effluent BOD concentration if the clarifier BOD removal rate is 30%? b) What is the clarifier TSS removal rate (%)? c) What is the expected average primary effluent TSS concentration
Problem #3: Biochemical Oxygen Demand (BOD) and Stream Quality A wastewater treatment plant designed for a...
Problem #3: Biochemical Oxygen Demand (BOD) and Stream Quality A wastewater treatment plant designed for a community of 45,000 people has a flow of 100 gal/person/day and a BOD5 loading of 0.2 lb/person/day. The upstream characteristics of the receiving waters are: stream flow rate = 20 cfs and BOD5 = 2 mg/L The water quality standards require the in-stream BOD5 to be less than 7 mg/L in this stretch of the river. The minimum BOD removal efficiency that the treatment...
A wastewater plant with the activated sludge process received 5 × 106 L/day of wastewater with...
A wastewater plant with the activated sludge process received 5 × 106 L/day of wastewater with a BOD5 of 500 mg/L. The primary clarifier removes 30% of the BOD and primary clarify effluent has no biomass (Xi=0 mg/L). Recycle (Qr) and waste sludge (Qw) flows are 25% and 2% of Qin, respectively. Effluent BOD5 from secondary clarifier and waste sludge is 20 mg/L. Microorganism concentration in the waste sludge (Xw) is 6,000 mg/L. Soluble BOD5 is biologically converted into CO2...
A complete mixed activated sludge process aeration tank treats 5 MLD sewage having the influent and...
A complete mixed activated sludge process aeration tank treats 5 MLD sewage having the influent and effluent soluble BOD concentrations of 220 and 20 mg/L respectively. The volume of the aeration tank is 5060 m3 and the mean cell residence time is 10 days. MLVSS in aeration tank is 3,400 mg/L, MLVSS/MLSS = 0.8 and sludge wastage rate is 1 m3/hour. Calculate the concentration of return sludge suspended solids ?
A completely mixed activated-sludge process is being designed for a wastewater flow of (2.64 mgd) using...
A completely mixed activated-sludge process is being designed for a wastewater flow of (2.64 mgd) using the kinetics equations. The influent BOD of 120 mg/Lis essentially all soluble and the design effluent soluble BOD is 7 mg/L, which is based on a total effluent BOD of 20 mg/L. For sizing the aeration tank, the mean cell residence time is selected to be10 days and the MLVSS 2000 mg/L. The kinetic constants from a bench-scale treatability study are as follows: Y...
The town of Camp Verde has been directed to upgrade its primary Waste Water Treatment Plant...
The town of Camp Verde has been directed to upgrade its primary Waste Water Treatment Plant (WWTP) to a secondary plant that can meet an effluent standard of 25 mg/L BOD5 and 30 mg/L suspended solids. They have selected a completely mixed activated sludge system for the upgrade. The existing primary treatment plant has a flow rate of 0.029 m3/s. The effluent from the primary tank has a BOD5 of 240 mg/L. Using the following assumptions, estimate the required volume...
A wastewater treatment plant receives an average of 3.0 MGD of wastewater flow. Two rectangular primary...
A wastewater treatment plant receives an average of 3.0 MGD of wastewater flow. Two rectangular primary clarifiers operating in parallel will treat the flow. If the length of each clarifier is four times its width, the width is 20 ft, and the depth is 10 ft, determine: a) the overflow rate in gpd/ft2. b) the detention time of each clarifier (in days).
You have been retained to design a wastewater treatment plant using a conventional activated sludge process...
You have been retained to design a wastewater treatment plant using a conventional activated sludge process for a town of 40,000 people. The industrial flow contribution to the sewer system is 300,000 gallons per day. Effluent discharge standards require effluent BOD5 and total suspended solids concentration of <10 mg/l. Assume the following design criteria are applicable: Domestic sewage flow = 100 gal/cap/day (including I/I) BOD loading = 0.18 lbs/cap/day TSS loading = 0.20 lbs/cap/day BOD removal in primary = 33%...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT