Question

# A surveyor's 30-m steel tape is correct at 68" role="presentation">°°° F. On a hot day, the...

A surveyor's 30-m steel tape is correct at 68" role="presentation">°°° F. On a hot day, the tape has expanded to 30.02 m. On that day, the tape indicates a distance of 15.52 m between two points. The true distance between these points is

Can you provide a step by step explanation? thanks!

From the given data, we can observe the tape is 30.02 and with this we measured 15.52 m. It clearly indicates that we assumed it was 30m but it is 30.02. means we have got less length than actual.so,

For 30m - 15.52m

Then 30.02 m - ?

Cross multiply ,then (30.02÷30)×15.52= 15.53m.

OR

For every 30 m we got 0.02m less,

Then 15.52 m how much extra tone added =(0.02÷30)×15.53= 0.01

Now, 15.52 + 0.01 =15.53m

You can understand in any way but be clear with that.or else with a formula ,

actual length = (incorrect length÷ correct length)× measured length

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