Question

Water flows with a velocity of 2m/s and at a depth of 3m in a rectangular channel. Neglect headlosses.
a) What is the change in depth and in water surface elevation produced by an upward change in elevation (up-step) of 60 cm?

(Answer with steps plz)

Answer 1

Given, velocity before stepup ,

Water depth before stepup =

Change in elevation (∆Z) = 60 cm = 0.6 m.

Initial Specific energy -

=>

=>

{ q = v * y = 3 * 2 = 6 m3/s/m }

Specific energy after stepup of 0.6 m.

=>

=>

As, we know initial specific energy = Specific energy after stepup.

Hence ,

=>

On solving ,

Hence, depth after stepup is 2.236 m.

If any doubt kindly comment. Thank you.