Question

6. An overflow spillway flows into a mild channel, producing a hydraulic jump. The channel is...

6. An overflow spillway flows into a mild channel, producing a hydraulic jump. The channel is rectangular, with Q = 100 ft3/s, bottom width b = 20 ft, and Manning's n = 0.015. The flow depth at the toe of the spillway is 0.4 ft and the approximate slope at the toe of the spillway is 0.1. The slope of the [mild] downstream channel, which functions as a stilling basin, is 0.0001. Calculate:

 the critical depth,  the length Ltc from the toe of the spillway to critical depth downstream,  the Froude number at the toe of the spillway,  the Froude number downstream of the hydraulic jump,  the sequent depth y2 (the normal depth downstream of the hydraulic jump),  the length Lj of the jump, assuming Lj = 6.2 y2  the minimum length of the stilling basin Lsb = Ltc + Lj

Homework Answers

Answer #1

Please give a?

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A long rectangular concrete channel (b = 10 ft, n = 0.015) carries 400 cfs. There...
A long rectangular concrete channel (b = 10 ft, n = 0.015) carries 400 cfs. There is a grade break in the channel; the slope upstream of the grade break is 0.02 and the slope downstream of the grade break is 0.002. The following equations are valid for a rectangular channel: • DC = [(Q2)/(g*b2)]1/3 • y2 = 0.5*y1*[(1+8NFr12)1/2 -1] (for hydraulic jump) • NFr = v/(g*y)1/2 a) Use calculations to classify each section of the channel (steep, mild, horizontal,...
A long rectangular concrete channel (b = 10 ft, n = 0.015) carries 400 cfs. There...
A long rectangular concrete channel (b = 10 ft, n = 0.015) carries 400 cfs. There is a grade break in the channel; the slope upstream of the grade break is 0.02 and the slope downstream of the grade break is 0.002. The following equations are valid for a rectangular channel: DC = [(Q2)/(g*b2)]1/3 y2 = 0.5*y1*[(1+8NFr12)1/2 -1] (for hydraulic jump) NFr = v/(g*y)1/2 a) Use calculations to classify each section of the channel (steep, mild, horizontal, adverse or critical)...
The 1.5 cm wide rectangular channel in the laboratory was used to create a hydraulic jump;...
The 1.5 cm wide rectangular channel in the laboratory was used to create a hydraulic jump; the following data were collected: y1 = 1.25 ± 0.05 cm; y2 = 5.6 ± 0.1 cm; Q = 8 liters/30 sec Assume the water temperature was 20°C. (Note the mixed units above – please present your solutions in si units) (a) Use the theoretical equation to predict the conjugate depth ratio, y2/y1, based on the initial depth, y1. Compare the value to the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT