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Traffic has ground to a halt on one direction of a six-lane freeway (three-lanes in each...

Traffic has ground to a halt on one direction of a six-lane freeway (three-lanes in each direction). The state Department of Transportation (DOT) reports that it observed from the state patrol helicopter a density of the stopped traffic of 52.8 veh/lane/mi. What would you expect that the average spacing of vehicles is?

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Answer #1

The density of the stopped traffic = 52.8 veh/lane/mi

= 0.0328 veh/lane/meter (1 mile = 1609.34m)

In general the average length of a passenger car unit is 6meter.

Therefore the total length occupied by the 52.8 vehicles per lane = 52.8x6

= 316.8 meters

The total unoccupied length/lane/mile = 1609.34 - 316.8

= 1292.54 meters

Number of unocupied space = 54 (you can assume 55 or 53 also)

Therefore the average spacing between the vehicles =

Hence the average spacing of vehicles in one lane in one mile is 24 meters.

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