Question

Two identical sedimentation tanks are to be designed for an activated sludge plant with a flow...

Two identical sedimentation tanks are to be designed for an activated sludge plant with a flow of 2 MGD (flow is split evenly between the two clarifiers). The MLSS will be 1950 mg/L. The underflow (return sludge) concentration will be 12,000 mg/L. A settling curve was developed (using a column with Ho = 2.13 ft) and is shown below. For clarification area use a safety factor of 2.0 and for thickening area use a safety factor of 5. Tanks are available in 5-ft increments. What is the area required for clarification (ft2)? 3200 ft2

Engineering   Civil-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

ANSWER:---

REQUIRED AREA FOR CLARIFICATION IS CALCULATED BELOW

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Two identical sedimentation tanks are to be designed for an activated sludge plant with a flow...
Two identical sedimentation tanks are to be designed for an activated sludge plant with a flow of 2 MGD (flow is split evenly between the two clarifiers). The MLSS will be 1950 mg/L. The underflow (return sludge) concentration will be 12,000 mg/L. A settling curve was developed (using a column with Ho = 2.13 ft) and is shown below. For clarification area use a safety factor of 2.0 and for thickening area use a safety factor of 1.5. Tanks are...
Two identical sedimentation tanks are to be designed for an activated sludge plant with a flow...
Two identical sedimentation tanks are to be designed for an activated sludge plant with a flow of 2 MGD (flow is split evenly between the two clarifiers). The MLSS will be 1950 mg/L. The underflow (return sludge) concentration will be 12,000 mg/L. A settling curve was developed (using a column with Ho = 2.13 ft) and is shown below. For clarification area use a safety factor of 2.0 and for thickening area use a safety factor of 1.5. Tanks are...
Mass of solids Generated from the activated sludge tanks. 13. Assume: The total design flow is...
Mass of solids Generated from the activated sludge tanks. 13. Assume: The total design flow is 3.75 MGD (15,000 m3/day). The NPDES limit is 25/30. Assume that the waste strength is 170 mg/L BOD after primary clarification. Y = 0.55 kg/kg. What is the mass of solids generated each day (Kg/day or lbs/day) in the activated sludge tankage?
ANSWER as much as possible: Design an activated sludge process consisting of a complete mix flow...
ANSWER as much as possible: Design an activated sludge process consisting of a complete mix flow through aeration tank followed by final settling tanks. The sizing of the reactor and all appurtenances should be based on a solids retention time, (SRT), of 4 days and the particulates given below. Biological characteristics: Ks = 20 mg/L COD, kd = 0.1 per day, mumax = 3 gVSS/gVSS-day,    Y = 0.4 gVSS/gCOD Primary settling Tank Effluent Characteristics: Q= 20MGD, biodegradable COD, bCOD...
An activated sludge system has three square reactor tanks in series (CFSTRs) that are each 60...
An activated sludge system has three square reactor tanks in series (CFSTRs) that are each 60 ft wide, 60 ft long, and 18 ft deep. The engineers have decided to add a new reactor in parallel. It will be a plug flow reactor (PFR) with a depth of 18 feet and a width of 18 feet. The length is to be calculated. The flowrate of wastewater is 2 MGD and the BOD is 165 mg/L. This will be split in...
A wastewater treatment plant that treats wastewater to secondary treatment standards uses a primary sedimentation process...
A wastewater treatment plant that treats wastewater to secondary treatment standards uses a primary sedimentation process followed by an activated sludge process composed of aeration tanks and a secondary clarifiers. This problem focuses on the activated sludge process. The activated sludge process receives a flow of 15 million gallons per day (MGD). The primary sedimentation process effluent has a BOD5 concentration of 180 mgBOD5/L (this concentration is often referred as S). Before flowing into the activated sludge process, the primary...
Dechlorination contact tank (Wastewater Treatment) An activated sludge plant has a design flow (average daily flow)...
Dechlorination contact tank (Wastewater Treatment) An activated sludge plant has a design flow (average daily flow) of 11 MGD. Determine dimensions of dechlorination tank. The design parameters: use 1 tank. detention time = 30 sec, depth = 10 ft, rectangular tank: L = 4 W. use maximum hourly flow (3 * Average design flow)
A completely mixed activated-sludge process is being designed for a wastewater flow of (2.64 mgd) using...
A completely mixed activated-sludge process is being designed for a wastewater flow of (2.64 mgd) using the kinetics equations. The influent BOD of 120 mg/Lis essentially all soluble and the design effluent soluble BOD is 7 mg/L, which is based on a total effluent BOD of 20 mg/L. For sizing the aeration tank, the mean cell residence time is selected to be10 days and the MLVSS 2000 mg/L. The kinetic constants from a bench-scale treatability study are as follows: Y...
You have been retained to design a wastewater treatment plant using a conventional activated sludge process...
You have been retained to design a wastewater treatment plant using a conventional activated sludge process for a town of 40,000 people. The industrial flow contribution to the sewer system is 300,000 gallons per day. Effluent discharge standards require effluent BOD5 and total suspended solids concentration of <10 mg/l. Assume the following design criteria are applicable: Domestic sewage flow = 100 gal/cap/day (including I/I) BOD loading = 0.18 lbs/cap/day TSS loading = 0.20 lbs/cap/day BOD removal in primary = 33%...
Problem #3: Biochemical Oxygen Demand (BOD) and Stream Quality A wastewater treatment plant designed for a...
Problem #3: Biochemical Oxygen Demand (BOD) and Stream Quality A wastewater treatment plant designed for a community of 45,000 people has a flow of 100 gal/person/day and a BOD5 loading of 0.2 lb/person/day. The upstream characteristics of the receiving waters are: stream flow rate = 20 cfs and BOD5 = 2 mg/L The water quality standards require the in-stream BOD5 to be less than 7 mg/L in this stretch of the river. The minimum BOD removal efficiency that the treatment...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT