Question

Estimate the peak flow for a new development area consists of 700 unit houses

and a market of 25 stalls.

Given:

Dry weather flow = 225 L/day/cap

Residential= 5 PE/unit

Market= 3 per stall

Peak flow = 4.7 x p

-0.11

x 0.0093 m

3

/s

Answer 1

given :

Dry weather flow = 225L/day/cap

residential = 5 pe / unit

market = 3 per stall

we need to find the peak flow for the new development area

Total number of person from houses/ residential = 5 * 700 = 3500

Total number of person from market = 3 * 25 = 75

peak flow from houses = 225 * 3500 = 787500 L/day

peak flow from market = 225 * 75 = 16875 L/day

Total peak flow (p) = 787500 + 16875 = 804375 L/day

we have to convert L/day into m³/s

[ 1 L = 10^-3 m³ ]

[ 1 day = 24 * 60 * 60 seconds ]

therefore, p = 0.0093 m³/s

According to formula,

Peak flow = ( 4.7 * p ) - ( 0.11 * 0.0093 )

putting the value of p, we get:

Peak flow = ( 4.7 * 0.0093 ) - ( 0.11 * 0.0093 )

Peak flow = 0.042687 m³/s

therefore, peak flow for new development area is 0.042687 m³/s