Question

Don’t worry yourself...just read and understand your book.... Q. The cement content in the mixture with 150 kg/m3 of water and water-cement ratio of 0.45 is ___________.

If moisture content is 5% and aggregate density is 500 kg/m3. The final weight of the aggregate is _______

If the moisture content of aggregate is 1% and absorption is 4%, the water contributed to the mixture is _________

...

If the fine aggregate is 300 kg/m3 and total aggregate is 1000 kg/m3, what is the weight of coarse aggregates_________

Answer 1

1. Cement content = (Water content) / (w/c)

= 150/0.45

Cement content = 333.33 kg

2. Aggregate density = 500 kg/m3

Moisture content = 5%

Final weight of aggregate = Aggregate density * ( 1 + moisture content)

Final weight of aggregate = 500 * (1 + 0.05)

Final weight of aggregate = 525 kg

3. Moisture content of aggregate = 1%

Absorbed water = 4%

Only moisture content contributes water to the mixture. Absorbed water is used only to adjust the quantity of aggregates.

Therefore,

Moisture contributed to the mixture = 1%

4. Fine aggregate = 300 kg/m3

Total aggregates = 1000 kg/m3

Total aggregates = Coarse aggregates + Fine aggregates

Therefore,

Weight of coarse aggregates = Total aggrgates - Fine aggregates

Weight of coarse aggregates = 1000 - 300

Weight of coarse aggregates = 700 kg/m3