Question

A 100-ft steel tape standardized at 68°F and supported throughout under a tension of 12 lb was found to be exactly 100.010 ft long. The tape had a cross-sectional area of 0.0075 in² and a weight of 2.25 lb. This tape is to be used to layout a distance AB of 529.81 ft under the following conditions: 95°F, supported throughout, tension of 20 lb. What length is required to layout the specified distance?

Answer 1

Standardization correction is given by

= 0.053 ft

Temperature correction is given by

= 0.092 ft

Since tape is supported throughout , sag correction is zero

Correction due to pull is given by

= 0.0195 ft

Length required to layout the specified distance is given by