Question

Determine the total that of sludge on a dry–solids basis that will be produced for each kilogram of alum [Al2(SO4)3·14H2O] added. Assume the TSS is equal to 12 mg/L.The alum dose = 30 mg/L.

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Determine the mass and volume of sludge produced and the volume
of sludge as a percentage of the total flow from the use of alum
[Al2(SO4)3·18H2O] for the removal of turbidity. Assume the
following conditions apply: (1) flow rate is 0.05 m3/s, (2) average
raw-water turbidity is 45 NTU, and (3) average alum dose is 40
mg/L, sludge solids concentration is 5 percent with a corresponding
specific gravity of 1.05, and temperature is 10◦C. Assume the ratio
between total suspended...

14. Sludge wasting rate (Qw) from the solids
residence time (Thetac = mcrt) calculation. Given the
following information from the previous problem. The total design
flow is 15,000 m3/day. Theoretical hydraulic detention
time (Theta) = 8 hours. The NPDES limit is 25 mg/L BOD/30 mg/L
TSS.
Assume that the waste strength is 170
mg/L BOD after primary clarification.
XA=MLSS = 2200 mg/L,
Xw = Xu =
XR = 6,600 mg/L,
qc = 8 days.
Make sure you account for the...

Mass of solids Generated from the activated sludge tanks.
13. Assume: The total design flow is 3.75 MGD (15,000
m3/day). The NPDES limit is 25/30. Assume that the waste
strength is 170 mg/L BOD after primary
clarification. Y = 0.55 kg/kg.
What is the mass of solids generated each day (Kg/day or
lbs/day) in the activated sludge tankage?

A completely mixed activated sludge process is designed to treat
20,000 m3 /d of domestic wastewater having a BOD5 concentration of
250 mg/L following primary treatment. The NPDES permit requirement
for effluent BOD5 and TSS is 20 mg/L for each. The biokinetic
parameters have been established as: yield = 0.6 , k = 5/d, Ks = 60
mg/L, and kd = 0.06/d. The MLVSS concentration in the aeration tank
is to be maintained at 3000 mg/L and the ratio of...

A water treatment plant with an average flow of Q = 0.044
m3/second treats its water with alum (Al2 (SO4)3 • 14H2O) at a dose
of 25 mg/L. Alum coagulation is used to reduce the concentration of
natural organic matter and reduce the alkalinity of water according
to the equation given below. Find the total mass of alkalinity
consumed. Assume all alkalinity to be bicarbonate. (10 points)
Al2(SO4)3 • 14H2O + 6HCO3- 2Al(OH)3 (s) + 6CO2 + 14H2O + 3SO2-4

A city of 150,000 people discharges sewage, after removing 90%
of the total suspended solids (TSS), into a stream with 0 TSS and a
flow of 50 m3/min. A newspaper critic stated that what
the city is doing is equivalent to discharging untreated sewage
from 15,000 people. Is this criticism fair? Assume that each person
produces 2.67 x 10-4 m3/min of wastewater
with a TSS concentration of 200 mg/L.

Sooner City Reclamation Plant is a completely mixed activated
sludge process designed to treat 20,000 m3/d of domestic
wastewater having an influent BOD5 concentration of 350
mg/L (assume a 28.6% reduction in during primary treatment). Use
typical activated sludge kinetic constants except for kd
= 0.06 1/d. Assume that the MLVSS concentration in the aeration
basin is maintained at 3,000 mg/L and the ratio of VSS:TSS is 0.75.
Permit requires that the effluent BOD5 and TSS
concentrations do not exceed...

Ferrous sulfate is added along with lime (CaO) to water to raise
the pH and form ferric hydroxide particles to aid coagulation.
Consider the reaction to be as follows:
2 FeSO4·7H2O + 2 CaO + 0.5 O2 → 2 Fe(OH)3(s) + 2 CaSO4 + 4
H2O
The ferrous sulfate dose is 40 mg/L.
THE MOST IMPORTANT PARTS TO ANSWER ARE b and d. Please
explain clearly and show ALL working. Its very useful to help me
understand the problem. THANKS!!!...

Ferric sulfate is available as a commercial coagulant, and is
effective for removing turbidity and color. The chemical reaction
for its addition to water is: Fe2(SO4)3 + 3Ca(HCO3)2 ----> 2
Fe(OH)3 (s) + 3CaSO4 + 6CO2 Results of a jar test to determine the
optimal coagulant dose showed that 20 mg/L of ferric sulfate was
optimal. The raw water has an alkalinity of 60 mg/L as CaCO3. a.
How much ferric sulfate is needed per day to treat 1 MGD....

You have been retained to design a wastewater treatment plant using
a conventional activated sludge process for a town of 40,000
people. The industrial flow contribution to the sewer system is
300,000 gallons per day. Effluent discharge standards require
effluent BOD5 and total suspended solids concentration of <10
mg/l.
Assume the following design criteria are applicable:
Domestic sewage flow = 100 gal/cap/day (including I/I)
BOD loading = 0.18 lbs/cap/day
TSS loading = 0.20 lbs/cap/day
BOD removal in primary = 33%...

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