A rectangular tank filled with water is moving horizontally of an acceleration that is half of g. If the tank is 4m long, what is the difference in pressure (kPa) between the rear end and front end of the tank? Place your answer in two decimal places
P1=pressure at point 1 = wh1
P2=pressure at point 2 = wh2
tan = ac/g = 1/2
tan = (h1-h2)/L
h1-h2= 0.5* L = 0.5 *4 = 2 m
pressure difference between rear and front end = P1-P2= wh1-wh2 = w(h1-h2)= 1000 *2*9.8 Pascal =19600Pa
= 19.6 Kpa
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