Question

A horizontal curve with a 300 intersecting angle on a two-lane
highway with 12-ft has a 60 mph design speed. The radius for the
horizontal curve has been set to 1,250 ft. The PI is located at
station 85 + 29.14 and the normal crown on the tangent is 2%.
Determine:

a) Tangent to Spiral (TS) station,

b) Spiral to Curve (SC) station,

c) Curve to Spiral (CS) station, and d) Spiral to Tangent (ST)
station.

Answer #1

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A horizontal curve with a 300 intersecting angle on a two-lane
highway with 12-ft has a 60 mph design speed. The radius for the
horizontal curve has been set to 1,250 ft. The PI is located at
station 85 + 29.14 and the normal crown on the tangent is 2%.
Determine:
a) Tangent to Spiral (TS) station,
b) Spiral to Curve (SC) station,
c) Curve to Spiral (CS) station, and d) Spiral to Tangent (ST)
station.

A horizontal curve on a three-lane highway with 12-ft lanes has
a PC located at station 10+00 and PT at station 13+70. The central
angle is 25 degrees, the superelevation is 4%, and 40 ft of
clearance is available between an obstruction and the centerline.
Determine the maximum safe design speed to the nearest 5 mph.

A horizontal curve is being designed for a new four-lane roadway
with 11-ft lanes. The PT is located at station 1050+20, the design
speed is 45 mph and maximum superelevation of 4%. If the central
angle of the curve is 30 degrees, what is the radius of the curve
and location of the PC and PI?

A single-lane racetrack is being constructed with a 150 mph
design speed. A curve on this track has a radius of 4500 ft,
central angle of 30 degrees, and a PI located at station 150+40. If
the coefficient of side friction is 0.3, what superelevation is
required for safe vehicle travel at the design speed? Also,
determine the length of the curve and station of the PC and PT.

ou are asked to design a horizontal curve for a two-lane road.
The road has 12-ft lanes. Due to expensive excavation, it is
determined that a maximum of 35 ft can be cleared from the road’s
centerline toward the inside lane to provide for stopping sight
distance. Also, local guidelines dictate a maximum superelevation
of 0.08 ft/ft.
Determine the design speed for this curve (mph)?

A horizontal curve of radius 5620 ft is designed for 60 mph. The
roadway is a 4-lane undivided highway with 12-ft lanes. A tree is
located on the inside of the curve only 42 ft from the center of
the road. Does it pose a stopping sight distance problem for the
drivers travelling at the design speed? Show all supporting
calculations.

A horizontal curve on a two lane road is 175 ft long and has a
radius of 500 ft to the center of the road. There is a tree 24 ft
from the edge of the road in the middle of the curve. The lanes of
the road are 12 ft wide each. What is the sight distance available
through this curve? Recommend a maximum safe speed limit (within 5
mph) for this curve.

1. A horizontal curve on a two-lane highway is designed with a
2000 ft radius, 12 ft lanes, and 60mph design speed. Determine the
distance that must be cleared from the inside edge of the inside
lane to provide a sufficient stopping sight distance.
2, A flexible pavement is constructed with 102 mm (4 inches) of
hot mix asphalt (HMA) wearing surface, 203 mm (8 inches) of
emulsion/aggregate-bituminous base, and 203 mm (8 inches) of
crushed stone subbase. The subgrade...

A section of a roadway has a horizontal curve with
superelevation of 6% and central angle of 40o. The
design speed of the section is 60 mph. There are two lanes on the
curve, each 12 ft wide. Determine:
(a) The degree of the curve.
(b) The length of the curve.
(c) The minimum distance of an obstruction from the centerline
of the innermost lane.

a highway curve for a rural two-lane road connects front and
back tangents at Station 74+30 at an angle (delta) of 38 degrees
16’ 31”. using the maximum allowable superelevation for the
curve,(a) what would be its minimum radius for design for a posted
speed of 55mph? (b) What would be the station locations of the PC
and PT for this curve? (c) If the inner radius was kept clear of
all visual obstructions out to a distance of 45...

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