Given for unequal tangent curve,
G1= -1%
G2= +2%
L1= 20 stations
L2= 30 stations
Taking 100 ft= 1station
L1= Length of first tangent of unequal curve = 20 *100 = 2000 ft
L2= Length of second tangent of unequal curve = 30 *100 = 3000 ft
So, length of PI1= 2000/2 =1000 ft
Length of PI2 = 3000/2 = 1500 ft
Assume, the elevation of intermediate PI = y ft
Elevation of PI1 = y + (1000*1)/100 = (y+10) ft
Elevation of PI2 = y + (1500*2)/100= (y+30) ft
Grade = ((y+30)-(y+10)) * 100 / (1000+1500) = 0.8 %
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