Component |
Fraction by Weight |
Food |
45 |
Paper |
30 |
Textiles |
10 |
Wood |
15 |
Ans) Given,
a) Using Khan's formula ,heat value of waste (MJ/kg) can be given by,
E = 0.051(F + 3.6 CP) + 0.352 (PLR)
where, F = fraction of food waste
CP = fraction of cardboard, wood and paper
PLR = fraction of plastic and rubber
E = 0.051(45 + 3.6(30+15) ) + 0.352(0)
E = 10.55 MJ/kg
b) To determine heat value on wet basis assume moisture content in each waste as:
Waste | Fraction by weight | Moisture content (%) | Dry weight |
Food | 45 | 70 | 13.5 |
Paper | 30 | 6 | 28.2 |
Textile | 10 | 10 | 9 |
Wood | 15 | 20 | 12 |
Now using, Khan formula,
E = 0.051(13.5 + 3.6(28.2+12) ) + 0.352(0)
E = 8.07 MJ/kg
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