Determine the design wind pressure using the simplified wind method for a building located in South Carolina with a basic wind speed of 110 mph, a height of 25 ft, a wind exposure of C, and an occupancy category of III. A) 29.8 B) 34.9 C) 31.4 D) 24.7
Given
Basic wind speed = 110 mph
height = 25 ft
wind exposure = C
occupancy category =III
CODE TO BE USED : ASCE 7
Design wind pressure = s30 (simplified wind method)
is adjustment factor for building height and exposure
I is Importance factor
Ps30 is simplified design pressure for exposure B at height 30 ft and I is 1
From ASCE 7
For height 25 ft and Exposure C : =1.35 (figure 6.2 ASCE 7)
For occupancy category III : I=1.15 (table 6-1 ASCE 7)
Ps30 =19.2 psf ( figure 6.2 ASCE 7)
Design wind pressure = (19.2)x(1.15)x(1.35)
=29.808 psf
ANSWER IS OPTION A
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