Question

Vertical Curve Information : VPISTA = 15+00      VPIELEV = 320.50 L = 800.00 g1=-4.00%   g2=+2.50% What...

Vertical Curve Information :

VPISTA = 15+00      VPIELEV = 320.50 L = 800.00 g1=-4.00%   g2=+2.50%

What is the elevation of the low point on the curve?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%;...
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35 ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.) Elevations on the curve at full stations f. (3 pts.) Elevations on the tangents at full stations g. (2 pts.) Tangent offsets at full stations h. (2 pts.) High/low...
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=1.75%, total length = 500.00’, length...
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=1.75%, total length = 500.00’, length of curve 1 is 150’, length of curve 2 is 350’, PVI station is 12+00, PVI elevation is 275.00’ Using the vertical curve, what is the station and elevation of the high/low point of the curve?
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=75%, total length = 500.00’, length...
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=75%, total length = 500.00’, length of curve 1 is 150’, length of curve 2 is 350’, PVI station is 12+00, PVI elevation is 275.00’ What is the elevation of the PCC? 276.98’ 277.63’ 285.63’ 265.12’
Given: L=200 ft equal tangent parabolic curve with g1 = -1.25%, g2 = +1.25%, VPI station...
Given: L=200 ft equal tangent parabolic curve with g1 = -1.25%, g2 = +1.25%, VPI station = 146+00, and VPI elevation = 1,895.00 ft. a. Compute stationing of BVC. b. Compute stationing of EVC. c. Compute rate of change, r. d. Compute elevation of BVC. e. Compute elevation at Station 145+50.
PI elev = 85.00 G1=-1%, G2=+2%, low elevation on curve is 103.00. Find L. Show work....
PI elev = 85.00 G1=-1%, G2=+2%, low elevation on curve is 103.00. Find L. Show work. a) 50 stations b) 55 stations c) 60 stations d) 65 stations.
A sag vertical curve is to join a grade of g1=−3.25% to a grade of g2=−1.00%....
A sag vertical curve is to join a grade of g1=−3.25% to a grade of g2=−1.00%. What is the minimum length of the curve for acceptable passing sight distance at night, with headlight illumination?
Use the following data to solve next 3 questions: A vertical curve with the following parameters:...
Use the following data to solve next 3 questions: A vertical curve with the following parameters: L = 600', g1 = -4%, g2 = -1%, STA_VPI = 25+00, ELEV_VPI = 672.05' The stations of the BVC and EVC are: a. 21+00 and 29+00 b. 19+00 and 31+00 c. 22+00 and 28+00 d. 20+00 and 27+00 The elevation of the BVC of the curve in the previous problem is: a. 669.05' b. 660.05' c. 684.05' d. 676.05' The elevation of the...
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft....
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft. The vertical curve is equal tangent, 600ft long, and connects an initial grade of +1.30% and a final grade of –1.10%. The vertical curve crosses a 3ft diameter pipe at right angles. The pipe is located at station 112 + 00 and its centerline is at elevation 1093.00 ft. a) Using offsets, determine the depth, below the surface of the curve, to the top...
If Sta. VPT= 40+30, L = 400 ft, G1= 3, G2 = -1.8%, and VPC Elev....
If Sta. VPT= 40+30, L = 400 ft, G1= 3, G2 = -1.8%, and VPC Elev. = 2563 ft. Calculate the elevations and stations at a. the low point, b. VPI, and c. VPC?
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to be connected by a vertical curve 400 ft long. The elevation of the BVC is 348.52. What is the... a. Elevation on the curve of the low/high point? b. Elevation of the curve at station 19+00 c. Elevation of the tangent at station 21+00 d. Elevation of the curve at station 21+50 e. Elevation of the curve at station 18+50
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT