Question

A simply supported rectangular beam of 5m span carries a characteristic dead, gk (inclusive of the beam’s self-weight) and imposed, qk, loads of 15 and 7 kN/m respectively.

Given the following data:

Beam: 285mm wide and 500mm high, Reinforcement steel: High tensile steel, Concrete grade: C30, Exposure condition: Mild and Fire resistance = 1.5h.

Design the rectangular beam according to BS8110.

Answer #1

A rectangular RC beam is simply supported over a span of 8m and
carries a dead load of 15kN/m (including self-weight) and an
imposed load of 8kN/m. The beam is 250mm wide and has an effective
depth of 400mm. Grade 30 concrete is to be used.
Determine if the beam should be singly reinforced or
doubly reinforced.

A 356 x 171 US45 steel beam is simply supported at the ends of a
span of 5.5 m. The beam carries a safe inclusive UDL of 12kN/m and
a point load of 75 kN at mid-span. Calculate the maximum deflection
due to this load.
Let:
E = 205 000 N/mm2
I = 12070 cm4
deflection δPL = PL/48EI
deflection δudL = 5wL3/384EI

A simply supported beam of 6m length carries a dead load of 10
kn/m and live load of 8 kn/m. It also support a point dead load of
60Kn at the centre. Using the formula calculate the moment
modification factor.

A rectangular, tension-reinforced beam is to be designed for
dead load of 500 lb/ft plus
self-weight and service live load of 1200 lb/ft, with a 22 ft
simple span. Material strengths will be fy =
60 ksi and fc・= 3 ksi for steel and concrete, respectively. The
total beam depth must not exceed 16
in. Calculate the required beam width and tensile steel
requirement, using a reinforcement
ratio of 0.60 ρ0.005 . Use ACI load factors and strength reduction
factors....

A simply supported beam is 3 m long. It carries a uniformly
distributed load of 6 kN/m throughout its span and a concentrated
load of 15 kN at a point 2 m from the left support. Assuming that
the beam has a rectangular shape whose width and depth are 150 mm
and 250 mm, respectively. Determine the maximum flexural stress in
MPa developed in the beam.

Please select the reinforcement spacing for the entire span of a
simply supported beam on a 22 ft span. Use the detailed method to
calculate Vc. Do not use a shear envelope diagram use the regular
shear force diagram. Use b = 16 in., d = 27 in., the main bending
reinforcement consists of 4 #9 bars. The unfactored dead and live
loads are 2.6 Kip/ft and 2.5 kip/ft, respectively, f’c = 4500 psi,
and fy = 60,000 psi. Use...

A simply supported beam spans 30 ft. and carries a uniformly
distributed dead load of 3.5 kip/ft,excluding the beam self-weight.
Also, in addition, a concentrated dead load of 15 kips and a
concentrated live load of 25kips, both act at the center of a 30 ft
span.Select the lightest-weight W-Shape to carry the load(A992
steel). Use LRFD method.

A simply supported beam spans 20 ft and carries a uniformly
distributed dead load of 0.8 kips/ft including the beam self-weight
and a live load of 2.3 kips/ft. Determine the required plastic
section modulus and select the lightest weight Wshape to carry the
moment. Consider only the limit state of yielding (Zone 1) and use
A992 steel. Design by (a) LRFD and (b) ASD.

analyse, design and report on a viable longitudinal span and
beam, suspend slab design and column slenderness.Design constraints
for this individual concrete beam include using simply supported
(fixed connected), non-continuous beam design and will not require
any pre stressed beam design based on AS3600-2009.
Support beams have a uniformly distributed imposed load of 15
kN/m
Density of RCC,ρ = 2600 kg/m3
Live Load on Slab = 4kN/m
Dead Load on Slab = 3kN/m
Yield Strength of...

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