Question

A 740 ft. long vertical curve is needed for a section of highway with an approaching...

A 740 ft. long vertical curve is needed for a section of highway with an approaching grade of -4.2% and a leaving grade of +1.6%. The station (in feet) of the Vertical Point of Intersection (VPI) is 16+70 and the elevation of the VPI is 609ft.

The station of the beginning of the curve is closest to:

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%;...
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35 ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.) Elevations on the curve at full stations f. (3 pts.) Elevations on the tangents at full stations g. (2 pts.) Tangent offsets at full stations h. (2 pts.) High/low...
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation...
A 1,800 ft. long sag vertical curve (equal tangent) has PVC at Station 145+10 and elevation 1,280 ft. The initial grade is -2.5% and final grade is +4.8%. Determine the elevation and stationing of PVI and PVT.
Problem #4: Vertical curve A vertical curve is define by gradient lines. The gradient of the...
Problem #4: Vertical curve A vertical curve is define by gradient lines. The gradient of the back tangent is +4.2% and the gradient of the forward tangent is -3.75%. The BVC station is at 45+00 and has an elevation of 215.00 feet. For a vertical curve with a length of 12 stations, determine the following: a. The station and elevation of the PVI. b. The station and elevation of the EVC. c. The elevation of the vertical curve at station...
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft....
The PVI of a vertical curve is at station 110 + 00 and elevation 1100.00 ft. The vertical curve is equal tangent, 600ft long, and connects an initial grade of +1.30% and a final grade of –1.10%. The vertical curve crosses a 3ft diameter pipe at right angles. The pipe is located at station 112 + 00 and its centerline is at elevation 1093.00 ft. a) Using offsets, determine the depth, below the surface of the curve, to the top...
An equal tangent sag vertical curve is 600 ft long (i.e. 6 stations). The elevation of...
An equal tangent sag vertical curve is 600 ft long (i.e. 6 stations). The elevation of PVC is 1000 ft. The initial grade is -0.035 ft/ft (-3.5%) and the final grade is +0.005 ft/ft (+0.5%). What is the elevation of a point that is 350 ft (3.5 stations) from PVC? A) 1005.42 ft B)991.83 ft C) 991.01 ft D) 996.83 ft
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade...
A vertical curve is needed to connect an entry grade of ‐2.4% to an exit grade of +1.5%. The PVI of the two grades is at station 33 + 75 and elevation of 540 m above the datum level. The elevation at station 34 + 40 must be 541 m above the datum level in order to Accommodate a street, which crosses the road. Determine; ( According to TRH17) i. The length of the curve. ii. The elevation and station...
A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the...
A vertical summit parabolic curve has vertical offset of 0.375 m. from the curve to the grade tangent at Station 10 + 050. The curve has a slope of +4% and -2% grades intersecting at the P.I. The offset distance of the curve at P.I. is equal to 1.5m. If the stationing of the P.C. is at 10 + 000. Compute the (a) required length of curve (b) horizontal distance of the vertical curve turning point from the point of...
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The...
A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The length of the curve is 450.00 ft. The intersection of the grades is at 10+00 and the elevation at that point is 440.00. Compute the elevation of the +00 points on the curve. Then determine the location and elevation of the highest point on the curve. If there is an existing bridge at this location over the proposed road, and the elevation of its...
3.9) Two level sections of an east-west highway (G=0) are to be connected. Currently, the two...
3.9) Two level sections of an east-west highway (G=0) are to be connected. Currently, the two sections of highway are separated by a 1200m (horizontal distance) ,2% grade.the westernmost section of highway is the higher of the two and is at elevation 30m. If the highway has a 100km/h design speed, determine, for the crest and sag vertical curves required, the stationing and elevation of the PVCs and PVTs given that the PVC of the crest curve (on the westernmost...
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3%...
An existing equal-tangent sag vertical curve is designed for 60 mi/h. The initial grade is -3% and the elevation of the PVT is 754 ft. The PVC of the curve is at station 134 + 16 and the PVI is at 137 + 32. An overpass is being constructed directly above the PVI. The highway is for cars only (AASHTO minimum and recommended structure clearances do not apply) and the overpass design assumes the driver's eye height is set conservatively...