Question

Use the following data to solve next 3 questions: A vertical curve with the following parameters:...

Use the following data to solve next 3 questions: A vertical curve with the following parameters: L = 600', g1 = -4%, g2 = -1%, STA_VPI = 25+00, ELEV_VPI = 672.05' The stations of the BVC and EVC are:

a. 21+00 and 29+00 b. 19+00 and 31+00 c. 22+00 and 28+00 d. 20+00 and 27+00

The elevation of the BVC of the curve in the previous problem is:

a.

669.05'
b.

660.05'
c.

684.05'
d.

676.05'

The elevation of the curve at station 25+00 is:

a.

673.55'
b.

674.30'
c.

671.30'
d.

672.80'
Engineering   Civil-Engineering   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

3rd sum at station 25+00 is already given in question

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%;...
For a vertical curve with the following data: L = 425.00 ft.; g1= -2.50%; g2= +0.90%; VPI sta = 28+50.00 ft.; VPI elev = 609.35 ft., determine the: a. (1 pt.) BVC station b. (1 pt.) EVC station c. (1 pt.) BVC elevation d. (1 pt.) EVC Elevation e. (3 pts.) Elevations on the curve at full stations f. (3 pts.) Elevations on the tangents at full stations g. (2 pts.) Tangent offsets at full stations h. (2 pts.) High/low...
Problem #4: Vertical curve A vertical curve is define by gradient lines. The gradient of the...
Problem #4: Vertical curve A vertical curve is define by gradient lines. The gradient of the back tangent is +4.2% and the gradient of the forward tangent is -3.75%. The BVC station is at 45+00 and has an elevation of 215.00 feet. For a vertical curve with a length of 12 stations, determine the following: a. The station and elevation of the PVI. b. The station and elevation of the EVC. c. The elevation of the vertical curve at station...
Given: L=200 ft equal tangent parabolic curve with g1 = -1.25%, g2 = +1.25%, VPI station...
Given: L=200 ft equal tangent parabolic curve with g1 = -1.25%, g2 = +1.25%, VPI station = 146+00, and VPI elevation = 1,895.00 ft. a. Compute stationing of BVC. b. Compute stationing of EVC. c. Compute rate of change, r. d. Compute elevation of BVC. e. Compute elevation at Station 145+50.
.A crest vertical curve joining a +3 percent and a-4 percent grade is to be designed...
.A crest vertical curve joining a +3 percent and a-4 percent grade is to be designed for 40 Km/h. If the tangents intersect at station (K20+ 60.00) at an elevation of 200 m, determine the stations and elevations of the BVC and EVC. Also, calculate the elevations of intermediate points on the curve at the whole stations.
A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0%...
A 3.0% grade passing at station 20+00.00 at an elevation of 99.10 m meets a -2.0% grade passing at station 20+50.00 at an elevation of 99.60 m. Please note that these two elevations and stations DO NOT correspond to BVC and EVC. a) Determine the station and elevation of the point of intersection of the two grades. b) If the highest point on the curve must lie at station 20+55.00, find the elevation of this point and the length of...
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=1.75%, total length = 500.00’, length...
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=1.75%, total length = 500.00’, length of curve 1 is 150’, length of curve 2 is 350’, PVI station is 12+00, PVI elevation is 275.00’ Using the vertical curve, what is the station and elevation of the high/low point of the curve?
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to...
A -6.00% grade and a +2.00% grade intersect at station 20+00. The two grades are to be connected by a vertical curve 400 ft long. The elevation of the BVC is 348.52. What is the... a. Elevation on the curve of the low/high point? b. Elevation of the curve at station 19+00 c. Elevation of the tangent at station 21+00 d. Elevation of the curve at station 21+50 e. Elevation of the curve at station 18+50
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=75%, total length = 500.00’, length...
An unequal tangent vertical curve has the following elements: g1=-3.25%, g2=75%, total length = 500.00’, length of curve 1 is 150’, length of curve 2 is 350’, PVI station is 12+00, PVI elevation is 275.00’ What is the elevation of the PCC? 276.98’ 277.63’ 285.63’ 265.12’
Problem 3.           A +2.35% grade meets a -2.20% grade at station 45+50.00 and elevation 695.00 feet...
Problem 3.           A +2.35% grade meets a -2.20% grade at station 45+50.00 and elevation 695.00 feet (PIVC or VPI). An 800-foot (8 station) vertical curve is planned. Draw a sketch and find the following: a. The station and elevation of the PCVC (BVC) (5 points) b. The station and elevation of the PTVC (EVC) (5 points) c. The elevation (on the curve) of station 44+00.00 (5 points) d. The vertical offset for station 44+00.00 (5 points) e. The station and...
A vertical parabolic curve is to connect a back tangent of -3% and a forward tangent...
A vertical parabolic curve is to connect a back tangent of -3% and a forward tangent of +4%. The change of grade is 0.60% per 20 m station. The stationing of PC is 17+428 with an elevation of 200 m. Compute the: a) length of the parabolic curve; b) stationing of PT (format: 00+000.00); c) elevation of PT; d) elevation of the lowest point of the curve; e) elevation at Station 17+544.67.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT