Question

for an standard spiral curve layout give the deflection angles and the total chord lengths from TS C

Answer 1

• Total chord length for a spiral curve from its beginning (TS or ST) to its end (SC or CS). CS = 100’ LS - 0.000338 a2(LS)5; also = √(X2 + Y2

• Chord length to any point on a spiral from TS or ST. CS’ = 100’ LS ‘ - 0.000338 a2(LS’)5; also = √ [(x’)2 + (y’)2]

• Deflection angle to any point on spiral measured from tangent at TS (or ST). df = a(LS’)2/6 - dfk in d
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• Deflection angle for full spiral measured from tangent at TS (or ST) to SC (or CS) respectively. DF = a(LS)2/6 - DFk; also DSLS/6 - DFk; also = DE/3 – DF

• Deflection angle for full spiral measured from tangent at TS (or ST) to SC (or CS) respectively. DF = a(LS)2/6 - DFk; also DSLS/6 - DFk; also = DE/3 – DFk