Question

An activated sludge system with recycle (CMFR) uses to treat primary effluent after sedimentation.Use the appropriate...

An activated sludge system with recycle (CMFR) uses to treat primary effluent after sedimentation.Use the appropriate kinetic coefficients for the influent water characteristics to CMFR. Influent Characteristics: Flow = 1000 m3/day; bsCOD= 192 g/m3; nbVSS= 30 g/m3; inert inorganics= 10 g/m3

Aeration Tank Data: MLVSS = 2500; g/m3; SRT or θc = 6-day

Calculate:

1.- Effluent bsCOD

2.- Hydraulic retention time

3.- Daily sludge production in Kg/day as

a) VSS

b)TSS

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A conventional activated sludge plant treating a domestic flow of 150 ML/d is operated at a...
A conventional activated sludge plant treating a domestic flow of 150 ML/d is operated at a SRT of 10 d with a MLVSS of 3500 ppm. The activated sludge plant is required to reduce the influent BOD from 200 ppm to less than 10 ppm prior to discharge. The discharge from the aeration basin is clarified, such that the clarifier overflow contains no particulate material and the MLVSS of the recycle stream is 8000 ppm. You are required to determine...
A completely mixed activated sludge process is designed to treat 20,000 m3 /d of domestic wastewater...
A completely mixed activated sludge process is designed to treat 20,000 m3 /d of domestic wastewater having a BOD5 concentration of 250 mg/L following primary treatment. The NPDES permit requirement for effluent BOD5 and TSS is 20 mg/L for each. The biokinetic parameters have been established as: yield = 0.6 , k = 5/d, Ks = 60 mg/L, and kd = 0.06/d. The MLVSS concentration in the aeration tank is to be maintained at 3000 mg/L and the ratio of...
ANSWER as much as possible: Design an activated sludge process consisting of a complete mix flow...
ANSWER as much as possible: Design an activated sludge process consisting of a complete mix flow through aeration tank followed by final settling tanks. The sizing of the reactor and all appurtenances should be based on a solids retention time, (SRT), of 4 days and the particulates given below. Biological characteristics: Ks = 20 mg/L COD, kd = 0.1 per day, mumax = 3 gVSS/gVSS-day,    Y = 0.4 gVSS/gCOD Primary settling Tank Effluent Characteristics: Q= 20MGD, biodegradable COD, bCOD...
A complete mixed activated sludge process aeration tank treats 5 MLD sewage having the influent and...
A complete mixed activated sludge process aeration tank treats 5 MLD sewage having the influent and effluent soluble BOD concentrations of 220 and 20 mg/L respectively. The volume of the aeration tank is 5060 m3 and the mean cell residence time is 10 days. MLVSS in aeration tank is 3,400 mg/L, MLVSS/MLSS = 0.8 and sludge wastage rate is 1 m3/hour. Calculate the concentration of return sludge suspended solids ?
Sooner City Reclamation Plant is a completely mixed activated sludge process designed to treat 20,000 m3/d...
Sooner City Reclamation Plant is a completely mixed activated sludge process designed to treat 20,000 m3/d of domestic wastewater having an influent BOD5 concentration of 350 mg/L (assume a 28.6% reduction in during primary treatment). Use typical activated sludge kinetic constants except for kd = 0.06 1/d. Assume that the MLVSS concentration in the aeration basin is maintained at 3,000 mg/L and the ratio of VSS:TSS is 0.75. Permit requires that the effluent BOD5 and TSS concentrations do not exceed...
A wastewater treatment plant that treats wastewater to secondary treatment standards uses a primary sedimentation process...
A wastewater treatment plant that treats wastewater to secondary treatment standards uses a primary sedimentation process followed by an activated sludge process composed of aeration tanks and a secondary clarifiers. This problem focuses on the activated sludge process. The activated sludge process receives a flow of 15 million gallons per day (MGD). The primary sedimentation process effluent has a BOD5 concentration of 180 mgBOD5/L (this concentration is often referred as S). Before flowing into the activated sludge process, the primary...
Estimate the volume of air to be supplied (m3/d) for an activated sludge system with a...
Estimate the volume of air to be supplied (m3/d) for an activated sludge system with a flow of 0.25 m3/sec, net waste activated sludge production of 340 kg/day VSS, and an influent soluble BOD5 of 74 mg/L. Assume that soluble BOD5 is 58% of BODL, BOD5 in the aeration tank is 14 mg/L, and that the oxygen transfer efficiency is 9%. Density of air is 1.185 kg/m3, and air has 23.2% oxygen.
A completely mixed activated-sludge process is being designed for a wastewater flow of (2.64 mgd) using...
A completely mixed activated-sludge process is being designed for a wastewater flow of (2.64 mgd) using the kinetics equations. The influent BOD of 120 mg/Lis essentially all soluble and the design effluent soluble BOD is 7 mg/L, which is based on a total effluent BOD of 20 mg/L. For sizing the aeration tank, the mean cell residence time is selected to be10 days and the MLVSS 2000 mg/L. The kinetic constants from a bench-scale treatability study are as follows: Y...
An activated sludge tank has the following characteristics: Q = 4.18 m3/sec; Influent BOD5 = 225...
An activated sludge tank has the following characteristics: Q = 4.18 m3/sec; Influent BOD5 = 225 mg/L; Effluent BOD5 = 4.5 mg/L; Ks = 100 mg/L; μm = 2.5 day-1; kd = 0.05 day-1. The mean cell residence time (MCRT) in days is most nearly: a.12.4 b.7.0 c.2.5 d.17.4 QUESTION 38 The hydraulic detention time, θc, of the activated sludge tank above (in Question #37) in hours is most nearly: (Note: Cells in the activated sludge tank, X = 3,500...
Design a completely mixed activated sludge process using three different design approaches (i.e. calculate the volume...
Design a completely mixed activated sludge process using three different design approaches (i.e. calculate the volume of the aeration basin). Base your design for the first approach on detention time, for the second one on BOD loading, and the third one on kinetics. The influent design flow rate to the activated sludge process is 10,000 m3 /day with a BOD5 concentration of 200mg/L. Completely mixed activated sludge processes typically have a detention time ranging from 3 to 6 hours and...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT