If I impose a torque at the center of a beam that has free ends, where would the maximum torsional angle occur.
The maximum torsional angle would occur at the point where , Torque is applied .( Means at the centre of beam )
Explanation :
=> At the free end the torsional angle would be zero , Because there is no torque acting at that point. It can be proved by the formula as shown , If T=0 , torsion angle = 0.
Also, Torsional angle is given as
,
And at the left hand side of the centre , The Length would decrease . Hence torsional angle would also decrease . As from the formula it is clear that torsion angle is propotional to length if all other terms are constant.
If any doubt kindly comment . Thank you.
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