Assuming that the smallest measurable wavelength in an experiment is 0.590 fm (femtometers), what is the maximum mass of an object traveling at 451 m·s–1 for which the de Broglie wavelength is observable?
= 0.59fm
= 0.59*10^-15 m [1fm = 10^-15 m]
v = 451m/sec
h = 6.625*10^-34 joule-sec
= h/mv
m = h/v
= 6.625*10^-34/0.59*10^-15*451 = 2.5*10^-21Kg >>>answer
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