Question

A reaction mixture contains 0.89 atm I2 and 1.77 atm I. Which of the following statements...

A reaction mixture contains 0.89 atm I2 and 1.77 atm I. Which of the following statements is TRUE concerning this system?

C will increase
C will decrease
Cannot be predicted
C will not change

Homework Answers

Answer #1

Answer – Given, reaction - I2(g) ↔ 2I(g) Kp = 0.209

When, I2 = 0.89 atm and I = 1.77 atm

So first we need to calculate the reaction quotient

reaction quotient Q p= P (I)2 / P (I2)

                                = (1.77)2 / 0.89

                                = 3.52

So Qp >Kp

So we know when Qp > Kp then there is reaction equilibrium shift towards the left side , means reactant side.

So answer is 3) The reaction will shift in the direction of reactants

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1)A system at equilibrium contains I2(g) at a pressure of 0.10 atm and I(g) at a...
1)A system at equilibrium contains I2(g) at a pressure of 0.10 atm and I(g) at a pressure of 0.16 atm . The system is then compressed to half its volume. A)Find the pressure of I2 when the system returns to equilibrium. Express your answer to two significant figures and include the appropriate units. i got 0.27 and was wrong 2)Solid carbon can react with gaseous water to form carbon monoxide gas and hydrogen gas. The equilibrium constant for the reaction...
At 400K, the equilibrium constant for the reaction I2(g) + F2(g) <==> 2 IF (g) Kp...
At 400K, the equilibrium constant for the reaction I2(g) + F2(g) <==> 2 IF (g) Kp = 7.0. A closed vessel at 400 K is charged with 1.46 atm I2, 1.46 atm F2, and 3.66 atm of IF. Which of the following statements is true? CAN YOU PLEASE EXPLAIN WHY? THANK YOU! A. The equilibrium partial pressures of I2 F2, and IF will not change. B. At equilibrium, the total pressure of IF wil be greater than 3.66 atm. C....
Consider the following reaction: H2(g)+I2(g)?2HI(g) A reaction mixture at equilibrium at 175 K contains PH2=0.958atm, PI2=0.877atm,...
Consider the following reaction: H2(g)+I2(g)?2HI(g) A reaction mixture at equilibrium at 175 K contains PH2=0.958atm, PI2=0.877atm, and PHI=0.020atm. A second reaction mixture, also at 175 K, contains PH2=PI2= 0.630 atm , and PHI= 0.102 atm . Is the second reaction at equilibrium? If not, what will be the partial pressure of HI when the reaction reaches equilibrium at 175 K?
Consider reaction I2(g)+Cl2(g)<======>2ICL(g) Kp=81.9 at 25 C A mixture at 25 C initially contains Pcl12=0.100 atm...
Consider reaction I2(g)+Cl2(g)<======>2ICL(g) Kp=81.9 at 25 C A mixture at 25 C initially contains Pcl12=0.100 atm PI2=0.100 PICl=0.100 Find the equilibrium partial pressures of I2,Cl2,and ICL at this temp. I want to know how to slove this problem with ICE table and show tips and ways around thanks.
A system at equilibrium contains I2(g) at a pressure of 0.33 atm and I(g) at a...
A system at equilibrium contains I2(g) at a pressure of 0.33 atm and I(g) at a pressure of 0.29 atm . The system is then compressed to half its volume. Part A Find the pressure of I2 when the system returns to equilibrium. Part B Find the pressure of I when the system returns to equilibrium.
A system at equilibrium contains I2(g) at a pressure of 0.19 atm and I(g) at a...
A system at equilibrium contains I2(g) at a pressure of 0.19 atm and I(g) at a pressure of 0.22 atm . The system is then compressed to half its volume. Part A: Find the pressure of I2 when the system returns to equilibrium Part B: Find the pressure of I when the system returns to equilibrium
Consider the reaction: H2(g)+I2(g)⇌2HI(g) A reaction mixture at equilibrium at 175 K contains PH2=0.958atm, PI2=0.877atm, and...
Consider the reaction: H2(g)+I2(g)⇌2HI(g) A reaction mixture at equilibrium at 175 K contains PH2=0.958atm, PI2=0.877atm, and PHI=0.020atm. A second reaction mixture, also at 175 K, contains PH2=PI2=0.629 atm , and PHI= 0.101 atm . Is the second reaction at equillibrium? I found that the kp=4.76X10-4 and Qp = .0257 So no, not at equillibrium. If not, what is the partial pressure of HI when the reaction reaches equilibrium at 175 K? I need help figuring out the ICE chart and...
Consider the following reaction: H2(g)+I2(g)⇌2HI(g) A reaction mixture at equilibrium at 175 Kcontains PH2=0.958atm, PI2=0.877atm, and...
Consider the following reaction: H2(g)+I2(g)⇌2HI(g) A reaction mixture at equilibrium at 175 Kcontains PH2=0.958atm, PI2=0.877atm, and PHI=0.020atm. A second reaction mixture, also at 175 K, contains PH2=PI2=0.622 atm , and PHI= 0.109 atm
An equilibrium mixture for the following reaction: H2(g) + I2(g) <---> 2HI(g) is composed of the...
An equilibrium mixture for the following reaction: H2(g) + I2(g) <---> 2HI(g) is composed of the following: P(I2) = 0.08592 atm; P(H2) = 0.08592 atm; P(HI) = 0.5996 atm. If this equilibrium is disturbed by adding more HI so that the partial pressure of HI is suddenly increased to 1.0000 atm, what will the partial pressures of each of the gases be when the system returns to equilibrium?   
A system at equilibrium contains I2(g) at a pressure of 0.23 atm and I(g) at a...
A system at equilibrium contains I2(g) at a pressure of 0.23 atm and I(g) at a pressure of 0.24 atm . The system is then compressed to half its volume. Find the pressure of I2 when the system returns to equilibrium. Express your answer to two significant figures and include the appropriate units. Find the pressure of I when the system returns to equilibrium. Express your answer to two significant figures and include the appropriate units.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT