The following data are obtained for the gas phase decomposition of acetaldehyde:
k (L/mole s) 0.0105 0.101 0.60 2.92
T (K) 700 750 800 850
Plot these data (ln k versus 1/T) and find the activation energy for the reaction.
Please show work and graph.
Plug in the datas in excel and plot the graph. Once you obtain the data, you get the following informations:
Since,
ln k = ln A - Ea/RT
ln k = (- Ea/R) (1/T) + ln A
y = mx + c straight line equation.
so, here slope = (- Ea/R)
and intercept = ln A
From the graph, we obtained
slope =-22261.9054
(- Ea/R) = -22261.9054
? Ea = 22261.9054 x R
? Ea = 22261.9054 x 8.314
= 185085.48 J / mol
= 185.08 kJ / mol
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