Question

# Given that 45.0 mL of nitrogen gas reacts with 65.0 mL of oxygen gas according to...

Given that 45.0 mL of nitrogen gas reacts with 65.0 mL of oxygen gas according to the reaction:

N2 (g) + 2 O2 (g) = 2 NO2 (g)

a) What is the limiting reactant?

b) Assuming constant conditions, what is the volume of NO2 produced?

a)

N2 (g) + 2 O2 (g) = 2 NO2 (g)

From the above reaction volume ratio of N2 and O2 is 1:2

Volume of O2 required to react with 45 mL N2 = = 90 mL O2

But we have only 60 mL of O2. So O2 voume is less

Therefore limiting reactant is O2

b)

Volume of NO2 produced = = 60 mL NO2

Volume of NO2 produced = 60 mL

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