A 2.90 g sample of an unknown chlorofluorocarbon is decomposed and produces 573 mL of chlorine gas at a pressure of 754 Torr and a temperature of 298 K. What is the percent chlorine (by mass) in the unknown chlorofluorocarbon?
V = 573ml = 0.573L
P = 754torr = 754/760 = 0.992atm
T = 298K
PV = nRT
n = PV/RT
= 0.992*0.573/0.0821*298 = 0.0232moles
mass of Cl2 = no of moles * gram molar mass
= 0.0232*71 = 1.6472g
The percent chlorine in the unknown chlorofluoro carbon = 1.6472*100/2.9 = 56.8% >>>>answer
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