Question

The hydrogen atomic emission spectrum includes a UV line with a wavelength of 92.323 nm. Photons...

The hydrogen atomic emission spectrum includes a UV line with a wavelength of 92.323 nm. Photons of this wavelength are emitted when the electron transitions to nf = 1 as the final energy state. Show all steps and round answers to correct sig figs.

a) Is this line associated with a transition between different excited states or between an excited state and the ground state?

b) What is the energy of the emitted photon with wavelength 92.323 nm?

c) What was the initial energy state, ni, of the electron in this transition? (Use your unrounded answer from (b).

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
An electron in an excited state of a hydrogen atom emits two photons in succession, the...
An electron in an excited state of a hydrogen atom emits two photons in succession, the first at 3037 nm and the second at 94.92 nm, to return to the ground state (n=1). For a given transition, the wavelength of the emitted photon corresponds to the difference in energy between the two energy levels. What were the principal quantum numbers of the initial and intermediate excited states involved?
Calculate the wavelength (in nm) of a photon emitted during a transition corresponding to the first...
Calculate the wavelength (in nm) of a photon emitted during a transition corresponding to the first line in the Balmer series (nf = 2) of the hydrogen emission spectrum.
The atomic line spectrum of hydrogen contains a line in the near-UV spectrum that corresponds to...
The atomic line spectrum of hydrogen contains a line in the near-UV spectrum that corresponds to an electron transitioning from an n = 7 orbital to an n = 2 orbital. What is the energy of the emitted photons that produce this line? I know the answer is 5.00 x 10^-19 J, I'm just unsure on how to go about solving it. Please give any equations used and where the numbers come from so I can try other problems on...
The electron in a hydrogen atom falls from an excited energy level to the ground state...
The electron in a hydrogen atom falls from an excited energy level to the ground state in two steps, causing the emission of photons with wavelengths of 656.5 nm and 121.6 nm (So the in the first step the 656.5 nm photon is emitted and in the second step the 121.6 nm photon is emitted). What is the principal quantum number (ni) of the initial excited energy level from which the electron falls?
The emission spectrum of hydrogen has a line at a wavelength of 922.6nm. A) Calculate the...
The emission spectrum of hydrogen has a line at a wavelength of 922.6nm. A) Calculate the energy change for the electron transition that corresponds to this line. B) This line is actually in the Paschen series. What are the initial and final values of n for the electron transition that corresponds to this line?
The wavelength 6.577 x 10^-5 cm is observed in the atomic emission spectrum of hydrogen. a....
The wavelength 6.577 x 10^-5 cm is observed in the atomic emission spectrum of hydrogen. a. Show that this is a transition line in the Balmer Series. b. What is the wavelength of the next higher-energy line?
Which statement(s) is/are true regarding the emission of a photon from a hydrogen atom? a. The...
Which statement(s) is/are true regarding the emission of a photon from a hydrogen atom? a. The emission of photons is an endothermic process, so ∆E is positive. b. The emission of photons is an exothermic process, so ∆E is negative. c. The wavelength of the ni = 3 to nf = 2 transition is shorter than the ni = 4 to nf = 2 transition. d. The energy of the ni = 3 to nf = 2 transition is greater...
Astronomers use the line emission from the quantum state n = 3 to n = 2...
Astronomers use the line emission from the quantum state n = 3 to n = 2 to probe ionized hydrogen gas – that is, hydrogen gas stripped of its electron. In ionization equilibrium, a balance is established between the process of ionization and its reverse, recombination, in which a free electron e − and proton p recombine to form neutral atomic hydrogen H, releasing one or more photons γ : e − + p ↔ H + γ The recombination...
1) The last two visible line observed in the Balmer series are of the wavelength 434.0...
1) The last two visible line observed in the Balmer series are of the wavelength 434.0 nm and 410.2 nm. For each of the wavelength, a) Determine the frequency associated with the photon associated with this wavelength. b) Determine the amount of energy released by this photon. c) The Balmer series are the results of excited electron at higher level relaxing to the electronic level of principle quantum number of nf = 2. Determine the excited electronic level, ni, of...
1) The aqua color line of the Balmer series occurs at 486.1 nm, a) Determine the...
1) The aqua color line of the Balmer series occurs at 486.1 nm, a) Determine the frequency associated with the photon associated with this wavelength b) Determine the amount of energy released by this photon. c) The Balmer series are the results of excited electron at higher level relaxing to the electronic level of principle quantum number of nf = 2. Determine the excited electronic level, ni, of this electron. d) If this excited electron has the same wavelength as...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT