Question

S + Cu+ 2H⁺→H₂S + Cu²⁺

In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.

Answer 1

S + Cu + 2H⁺ ------------> H₂S + Cu²⁺

0     0                                  -2      +2 ----------->   oxidation states

here :S oxidation state changes from 0 to -2 . so this is reduced .

Cu oxidation state changes from 0 to +2. so Cu is oxidized

element reduced = S

element oxidized = Cu

oxidizing agent = S

reducing agent. = Cu