Balance the chemical equation a×C8H18 + b×O2 》c×CO2 + d×H2O for the combustion reaction of octane by determining the numbers a,b,c, and d
For combustion equations, it is better to balance in this order
a×C8H18 + b×O2 》c×CO2 + d×H2O
C8H18 +O2 --> CO2 + H2O
balance C
C8H18 +O2 --> 8CO2 + H2O
now balance H
C8H18 +O2 --> 8CO2 + 9H2O
finally balance O
total O in right --> 8*2 + 9*1 = 16+9 = 25
so.. 25/2 = 12.5
C8H18 +25/2O2 --> 8CO2 + 9H2O
if b can't be stated as a fraction, choose 12.5
if no decimals can be stated, then multiply by 2 to get whole numbers (integers)
2 (C8H18 +25/2O2 --> 8CO2 + 9H2O)
2C8H18 +25O2 --> 16CO2 + 18H2O
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