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If the liquid film resistance is 5 times that of the gas film for a gas...

If the liquid film resistance is 5 times that of the gas film for a gas absorption process, by how much would the rate absorption change if the liquid film coefficient could be doubled without changing other parameters?
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Answer #1

Given , Liquid resistance = 5x

gas resistance = x

Total resistance = 5x2 /6x = 5x/6

Now, K of liquid is two times the old K.

So, resistance will be 1/2 of old resistance.

So,

liquid resistance = 2.5x

gas resistance = x

Total resistance = (2.5x)*(x) /(2.5x+x)

=5x/7

We know rate is inversly proportional to resistance.

So,

New rate / old rate = old resistance / new resistance

= (5x/6) / (5x/7)

= 7/6

New rate / old rate = 1.167 times increase in rate

Percentage change = 16.7%

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