WHAT IS THE [OH-] OF A SOLUTION WITH A PH OF 9.0?
A)1 x 10-5 M
B) 1 x 10-9 M
C) 1 x 10-4 M
D) 1 x 10-7 M
E) NONE
pH = 9
Using pH we can calculate the concentration of [H+] ions using the formula
pH = - log [H+]
9 = - log [H+]
Taking minus to the left side, we get
-9 = log [H+]
[H+] = 10-9 M
We know that at 25 degree centrigrade, Kw of water is 1 x 10-14 M2
Kw (Ionic Product of water) = [H+][OH-] = 1 x 10-14 M2
Substituting the value of [H+] we can find the concentration of hydroxide ions ([OH-]
[OH-] = 1 x 10-14 / [H+] = 1 x 10-14 / 1 x 10-9 = 10-5
[OH-] = 1 x 10-5 M
Answer A
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