Question

Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV)...

Chlorine gas can be prepared in the laboratory by the reaction of hydrochloric acid with manganese(IV) oxide.

4HCl(aq)+MnO2(s)⟶MnCl2(aq)+2H2O(l)+Cl2(g)

A sample of 35.7 g MnO2 is added to a solution containing 43.1 g HCl.

what is the limiting reactant

What is the theoretical yield of Cl2?

If the yield of the reaction is 71.5%, what is the actual yield of chlorine?

Homework Answers

Answer #1

4HCl(aq)+MnO2(s)⟶MnCl2(aq)+2H2O(l)+Cl2(g)

according to balanced reaction

4 x 36.46 g HCl reacts with 86.94 g MnO2

43.1 g HCl reacts with 43.1 x 86.94 / 4 x 36.46 = 3747.114 / 145.84 = 25.69 g MnO2

but we have 35.7 g MnO2. so MnO2 is exess reagent

Limiting reagent = HCl.

4 x 36.46 g HCl gives 71 g Cl2

43.1 g HCl gives 43.1 x 71 / 4 x 36.46 = 20.98 g

therotical yield of Cl2 = 20.98 g

% yield = (actual yield / therotical yield) x 100

71.5 = (actual yield / 20.98) x 100

actual yield / 20.98 = 0.715

actual yield of CL2 = 15.00 g

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