Question

1. Microwave radiation has wavelengths from 1.0×10-3 to 1.0 m, whereas the wavelength region for infrared radiation is 1.0×10-6 to 1.0×10-3 m. We can say that: (higher than, lower than, or the same)

1. The frequency of microwave radiation is infrared radiation.

2. The speed of microwave radiation is infrared radiation.

2.Infrared radiation has frequencies from 3.0×1011 to 3.0×1014 Hz, whereas the frequency region for microwave radiation is 3.0×108 to 3.0×1011 Hz. (higher than, lower than, or the same) We can say that:

1. The speed of infrared radiation is microwave radiation.

2. The wavelength of infrared radiation is microwave radiation.

3.A local AM radio station broadcasts at a frequency of 884 kHz. Calculate the wavelength at which it is broadcasting. Wavelength = m (1 kHz = 10 3 sec -1)

4. A local FM radio station broadcasts at a frequency of 99.6 MHz. Calculate the wavelength at which it is broadcasting. Wavelength = meter (1 MHz = 106 s -1)

5. A local FM radio station broadcasts at a frequency of 107.1 MHz. Calculate the energy of the frequency at which it is broadcasting. Energy = kJ/photon (1 MHz = 106 sec -1)

6. A local AM radio station broadcasts at an energy of 5.90×10-31 kJ/photon. Calculate the frequency at which it is broadcasting. Frequency = KHz (1 KHz = 103 sec -1)

7. Calculate the energy of an electron in the n = 4 level of a hydrogen atom. Energy = Joules

8. Calculate the energy for the transition of an electron from the n = 8 level to the n = 6 level of a hydrogen atom. E = Joules Is this an Absorption (A) or an Emission (E) process

9. If the value of n = 4 ... The quantum number l can have values from to . ... The total number of orbitals possible at the n = 4 energy level is .

10. If the value of l = 2 ... The quantum number ml can have values from to . ... The total number of orbitals possible at the l = 2 sublevel is .

Answer 1

frequency and wavelength are related as

frequncy = velocity of light / avelength

thus they are inversely proportional.

1)wavelength of microwave is higher than infra red. Thus

i) the frequency of microwave is lower than infra red.

ii) the speed of microwve is equal to infra red [As all elecromagentic radiatio travel with the speed of light]

2)

i) the speed of infra red and microwave is same.

ii) the wavlength of infrared is less than microwave.

3)frquencey = 884kHz = 884x10³ /sec

Wavelength = velocity/frequency

= 3.0x10⁸m/sec / 884x10³/sec

= 339.36 m

4) frequency = 99.6MHz = 99.6x10⁶ /sec

thus  

wavelength = 3.0xx10⁸m/sec / 99.6x10⁶/sec

= 3.012 m

5) energy = h x frequency

h = Planck's constant = 6.626x10^-34 J.sec

Given frequency = 107.1 MHz = 107.1 x 10⁶ /sec

Thus energy = 6.626x10^-34 J.sec x107.1 x 10⁶ /sec

= 7.09 x 10^-26 J

=7.09x10^-29 kJ/photon

6)