Write the balanced reaction for the mixing of aqueous calcium nitrate and aqueous aluminum sulfate which produces solid calcium sulfate and aqueous aluminum nitrate. How many grams of aluminum sulfate would be needed to produce 1.5 grams of aluminum nitrate?
balanced equation:
3Ca(NO3)2 + Al2(SO4)3 ----------------------------------> 3CaSO4 + 2Al (NO3)3
problem :
3Ca(NO3)2 + Al2(SO4)3 ----------------------------------> 3CaSO4 + 2Al (NO3)3
342.15g 2x 212.996 g
? 1.5g
342.15g Al2(SO4)3 gives -------------------------> 425.992 g Al (NO3)3
x g Al2(SO4)3 gives ------------------------------> 1.5 g Al (NO3)3
x = 342.15 x 1.5 / 425.992
x = 1.2g
1.2 g aluminium sulfate is needed
Get Answers For Free
Most questions answered within 1 hours.