Question

An electrolytic cell is set up using a solution of aqueous Cu(NO3)2, and an external 6V...

An electrolytic cell is set up using a solution of aqueous Cu(NO3)2, and an external 6V

battery is connected to two inert electrodes which are dipped into the solution. If a current of 113

mA flows through the cell for 30.00 minutes, what mass of solid copper metal will be produced at

the cathode?

Homework Answers

Answer #1

This problem is based of Electrolysis,

I = 113 mA = 0.113 A,

t = 30.00 min = 30.00 x 60 = 1800 s

F = Faraday's constant = 96485 C/mol

z = # of electrons transfered = 2

as, (Cu(NO3)2 --------> Cu2+ (aq.) + 2 NO3- (aq.

Cu2+ (aq.) + 2e- ---------> Cu(0)

M =Molar mass of Cu(NO3)2 = 187.56 g/mole.

m =Mass liberated = ?

Formula (by Faradays 1st and 2nd law of electrolysis)

m = ItM /zF

on substituting values,

m = 0.113 x 1800 x 187.56 / (2x96485)

m = 0.198 Kg.

m = 198 g

Mass of solid Cu deposited will be 198 g.

========================XXXXXXXXXXXXXXXXXXXXX======================

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
1. You titrate a 10.00 mL sample of a solution of borax with HCl. If it...
1. You titrate a 10.00 mL sample of a solution of borax with HCl. If it requires 24.89 mL of 0.100 M HCl to reach the endpoint, calculate Ksp for borax. ______M 2. Considering the information given and the calculations performed, how many significant figures should properly be reported for the answer to the previous question. A. 2 B. 3 C. 4 D. 5 3. You measure Ksp for borax to be 7.8 x 10-3 and 2.9 x 10-3 at...
In this experiment you will construct a smal electrolytic cell. Then using indicators you will determine...
In this experiment you will construct a smal electrolytic cell. Then using indicators you will determine the products fromed at the anode and the cathode druing several different electrolysis experiments. About the experiment: in the first part of this experiment you will construct a small scale chlorine production plant. it is a miniature of the real, large scale process used for production of chlorine by the electrolysis of sodium chloride or brine (procedure written by Dr. Stephen thompson, CSU, CO)...
Reaction 1. a) For each mole of Cu dissolved in the nitric acid solution (HNO3), how...
Reaction 1. a) For each mole of Cu dissolved in the nitric acid solution (HNO3), how many moles of [Cu(H2O)6]2+ are formed? b) Given your data above, how many moles of [Cu(H2O)6]2+ were formed in your reaction? Reaction I: Cu (s) + 4 H3O+(aq) + 2 NO3-(aq) --> [Cu(H2O)6]2+(aq) + 2 NO2(g) The first reaction in the series is an oxidation – reduction reaction where copper metal“dissolves” in nitric acid (HNO3). Anoxidation – reduction reactionoccurs when one atomgains an electron...
Procedure Reaction 1: Dissolving the Copper 1. Obtain a clean, dry, glass centrifuge tube. 2. Place...
Procedure Reaction 1: Dissolving the Copper 1. Obtain a clean, dry, glass centrifuge tube. 2. Place a piece of copper wire in a weighing paper, determine the mass of the wire and place it in the centrifuge tube. The copper wire should weigh less than 0.0200 grams. 3. In a fume hood, add seven drops of concentrated nitric acid to the reaction tube so that the copper metal dissolves completely. Describe your observations in the lab report. (Caution, Concentrated nitric...
Chemical Reactions Types and Their Equations Making Heat with Chemical Reactions Have you ever wondered how...
Chemical Reactions Types and Their Equations Making Heat with Chemical Reactions Have you ever wondered how an instant heat pack works? A disposable heat pack works by a chemical reaction that combines iron in the package with oxygen from the air when the outer packaging is removed producing iron oxide. You have probably seen the product of this reaction in what is commonly called rust. The reaction releases heat, which allows the pack to reach a sufficient temperature that is...