Question

Time(s)	Concentration (M)
	N2O5	NO2	O2
0	0.0200	0	0
100	0.0169	0.0063	0.0016
200	0.0142	0.0115	0.0029
300	0.0120	0.0160	0.0040
400	0.0101	0.0197	0.0049
500	0.0086	0.0229	0.0057
600	0.0072	0.0256	0.0064
700	0.0061	0.0278	0.0070

Concentrations as a Function of Time at 55 ∘ for the Reaction
2N2O5(g)⟶4NO2(g)+O2(g)

A) Use the data in the table to calculate the average rate of decomposition of N2O5 during the time interval 100-200 s

B) Use the data in the table to calculate the average rate of formation of O2 during the time interval 100-200 s.

.

Answer 1

A. At 100 sec N2O5 = 0.0169

At 200 sec N2O5 = 0.0142

Rate of reaction =

( final concentration - initial concentration ) / time

= ( 0.0142 - 0.0169 ) / ( 200 - 100 )

= -2.7*10^-5 ( -ve sign means concentration is decreasing)

B. At 100 sec O2 = 0.0063

At 200 sec O2 = 0.0115

Rate of reaction =

( 0.0115 - 0.0063 ) / ( 200 - 100 )

= 5.2*10^-5 M/s ( +ve sign means concentration is increasing)

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