Question

1)What is the molar concentration of hydoxide ions in a solution made by dissolving 87.4 mg...

1)What is the molar concentration of hydoxide ions in a solution made by dissolving 87.4 mg of anhydrous magnesium hydroxide (58.3197 g/mol) in water for a final volume of 3.00 L?

1B)Which of the following is a precipitation reaction?

A) NH4Cl(aq) + KOH(aq) → KCl(aq) + NH3(g) + H2O(l) B) MgSO4(aq) + Ba(NO3)2(aq) → Mg(NO3)2(aq) + BaSO4(s) C) 2 HClO4(aq) + Ca(OH)2(aq) → 2 H2O(l) + Ca(ClO4)2(aq) D) LiCl(aq) + NaNO3(aq) → LiNO3(aq) + NaCl(aq) E) None of the above are precipitation reactions.

1C)Give the complete ionic equation for the reaction (if any) that occurs when aqueous solutions of potassium sulfate and lead (II) nitrate are mixed. A) 2 K+(aq) + S2-(aq) + Pb2+(aq) + 2 NO3-(aq) → PbS(s) + 2 K+(aq) + 2 NO3-(aq) B) 2 K+(aq) + SO42-(aq) + Pb2+(aq) + 2 NO3-(aq) → PbSO4(s) + 2 K+(aq) + 2 NO3-(aq) C) 6 K+(aq) + 3 SO42-(aq) + 3 Pb2+(aq) + 2 N3-(aq) → 3 PbSO4(s) + 6 K+(aq) + 2 N3-(aq) D) 2 K+(aq) + SO42-(aq) + Pb2+(aq) + 2 NO3-(aq) → Pb2+(aq) + SO42-(aq) + 2 KNO3(s) E) No reaction occurs.

Homework Answers

Answer #1

1)

mass = 87.4 mg = 0.0874 g

molar mass = 58.3197 g / mol

moles = mass / molar mass = 0.0874 / 58.3197 = 1.50 x 10^-3

molarity = moles / volume = 1.50 x 10^-3 / 3.0 = 5.0 x 10^-4 M

molar concentration of hydoxide ions   = 2 x 5.0 x 10^-4 M

                                                            = 9.99 x 10^-4 M

B) a precipitation reaction always forms solid so

answer : B) MgSO4(aq) + Ba(NO3)2(aq) → Mg(NO3)2(aq) + BaSO4(s)

C) answer :

B) 2 K+(aq) + SO42-(aq) + Pb2+(aq) + 2 NO3-(aq) → PbSO4(s) + 2 K+(aq) + 2 NO3-(aq)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Determine the type of reaction. ZnCO3(s) → ZnO(s) + CO2(g) HClO4(aq) + Mg(s) → Mg(ClO4)(aq) +...
Determine the type of reaction. ZnCO3(s) → ZnO(s) + CO2(g) HClO4(aq) + Mg(s) → Mg(ClO4)(aq) + H2(g) HBr(g) + F2(g) → HF(g) + Br2(g) H2O(l) → H2(g) + O2(g) Na2S(aq) + Cd(NO3)2(aq) → CdS(s) + NaNO3(aq)
1 What is the molarity of a solution made by dissolving 4.17 g of magnesium nitrate...
1 What is the molarity of a solution made by dissolving 4.17 g of magnesium nitrate [Mg(NO3)2] in enough water to make 22.0 mL of solution 2 Upon heating 118 g MgSO4 · 7 H2O: (a) how many grams of water can be obtained? (b) how many grams of anhydrous compound can be obtained?
1) For a galvanic cell that uses the following two half-reactions, Cr2O72-(aq) + 14 H+(aq) +...
1) For a galvanic cell that uses the following two half-reactions, Cr2O72-(aq) + 14 H+(aq) + 6 e- → 2 Cr3+(aq) + 7 H2O(l) Pb(s) → Pb2+(aq) + 2 e how many moles of Pb(s) are oxidized by one mole of Cr2O72-? A) 6 B) 2 C) 1 D) 3 2) What species is oxidized in the reaction: CuSO4(aq) + Mg(s) →MgSO4(aq) + Cu(s)? A) MgSO4 (aq) B ) M g (s) C ) C u S O 4 (aq)...
Concept: During the first week of this project, you need to synthesize several common kidney stones...
Concept: During the first week of this project, you need to synthesize several common kidney stones by precipitation reactions (Make sure that you save the kidney stones for week 2). You need to choose the reactants in a way that the kidney stone is the only product that precipitates out from the solution, while all other products remain soluble in water. This way the precipitate (kidney stone) can be separated from the rest of the solution by either filtration or...
Identify each of the following balance chemical reactions as either precipitation, oxidation-reduction (redox), and/or acid-based neutralization...
Identify each of the following balance chemical reactions as either precipitation, oxidation-reduction (redox), and/or acid-based neutralization reaction. A) Mg(s) + 2 HCL(aq) -----> MgCl2(aq) + H2(g) B) KOH(aq) + HNO3(aq) ------> KNO3(aq) + H2O(l) C) Pb(NO3)2(aq) + 2HBr(aq) ------> PbBr2(s) + 2HNO3(aq) D) Ca(OH)2(aq) + H2SO4(aq) -----> 2H2O(l) + CaSO4(aq) E) 2FeO3 + 3C(s) ----> 4Fe(s) + 3CO(g) F) 2Cr(NO3)3(aq) + 3Na2S(aq) -----> Cr2S3(s) + 6NaNO3(aq) G) 2Fe(s) + 3H2O(g) -----> Fe2O3(s) + 3H2(g) H) 2KOH(aq) + MnBr2(aq) -----> Mn(OH)2(s)...
solution is made by dissolving 20.0 g of magnesium metal in enough water to form magnesium...
solution is made by dissolving 20.0 g of magnesium metal in enough water to form magnesium hydroxide and hydrogen at constant pressure of 785 torr and 25.0 °C according to the following unbalanced chemical reaction: Mg(s) + H2O (l) → Mg(OH)2 (aq) + H2 (g) Compound ∆H°f (kJ/mole) Mg(OH)2 (aq) -924.5 H2O(l) -285.8 H2(g) 0.00 Mg(s) 0.00 Calculate ∆H° of the reaction in kJ/mol Mg. Calculate ∆H° of the reaction in kJ/gram of Mg If the initial volume of the...
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at...
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) F2(g) + 2 e- 2 F-(aq) 2.87 Ce4+(aq) + e- Ce3+(aq) 1.61 MnO4-(aq) + 8 H+(aq) + 5 e- Mn2+(aq) + 4 H2O(l) 1.51 Cl2(g) + 2 e- 2 Cl-(aq) 1.36 Cr2O72-(aq) + 14 H+(aq) + 6 e- 2 Cr3+(aq) + 7 H2O(l) 1.33 O2(g) + 4 H+(aq) + 4 e- 2 H2O(l) 1.229 Br2(l) + 2 e-...
1). The following reaction occurs in basic solution. Identify the oxidizing agent. (Note: The equation is...
1). The following reaction occurs in basic solution. Identify the oxidizing agent. (Note: The equation is not balanced.) Zn(s) + NO3-(aq) ® Zn(OH)42-(aq) + NH3(aq) OH-(aq) NO3-(aq) H2O(mc010-1.jpg ) Zn(s) NH3(aq) 2). Ethylene glycol is used in automobile radiators as an antifreeze. Use the following information to determine the freezing point of an antifreeze solution made by mixing 2.5 L of ethylene glycol with 2.5 L of water. Ethylene glycol is essentially nonvolatile and it does not dissociate in water....
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at...
Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) Standard Reduction (Electrode) Potentials at 25 oC Half-Cell Reaction Eo (volts) F2(g) + 2 e- 2 F-(aq) 2.87 Ce4+(aq) + e- Ce3+(aq) 1.61 MnO4-(aq) + 8 H+(aq) + 5 e- Mn2+(aq) + 4 H2O(l) 1.51 Cl2(g) + 2 e- 2 Cl-(aq) 1.36 Cr2O72-(aq) + 14 H+(aq) + 6 e- 2 Cr3+(aq) + 7 H2O(l) 1.33 O2(g) + 4 H+(aq) + 4 e- 2 H2O(l) 1.229 Br2(l) + 2 e-...
1. For each of the following, explain whether the substances can form a solution or not....
1. For each of the following, explain whether the substances can form a solution or not. A. NH3 and NaCl CH4 B. KBr C4H10 C. CO2 2. Classify the following compounds as strong electrolytes, weak electrolytes or non-electrolytes based on their dissolution reactions in water. A. C6H12O6(s)→C6H12O6(aq) B. Na3PO4(s)→3 Na(aq)+PO43(aq) C. AgCl(s)↔Ag+(aq)+Cl+(aq) D. Mg(NO3)2(s)→Mg2+(aq)+2 NO3-(aq) 3. Write the balanced total ionic equation and net ionic equation for the reaction that occurs when and (NH4)2CO3(aq) and MgSO4(aq) are mixed. 4. What...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT