Question

A mixture of helium and krypton gases is maintained in a 5.42 L flask at a pressure of 1.80 atm and a temperature of 71 °C. If the gas mixture contains 0.834 grams of helium, the number of grams of krypton in the mixture is ________ g

Answer 1

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Soli By ideal gas equation: PV= nRT P= 1.80 atm v= 5.42L T= fit 273 = 344K R = 0.08206 n = nuefnkg nue = 0.834 = 0.2085 84 1.80 x 5.42 =10.2085+ x x 0.08206 X 344 84 1.80 5.42 10. 2085+ x 2 0.2085+ x = : 84 344 X 0.08206 9.756 28.22 0. 319-0.2085 x = 84 x = 0.11058 84 x = 9.282 grams no. of grams of krypton - mixture in the