Question

Calculate the amount of energy released when 120.0g of diethyl ether (MW = 74.12 g/mol) is...

Calculate the amount of energy released when 120.0g of diethyl ether (MW = 74.12 g/mol) is cooled from 53.0 C to 10.0 C ?

boiling point = 26.02 KJ/mol

specific heat capacity, (CH3)2 O(I) 3.74 J/(g.k)

specific heat capacity, (CH3)2 O(g) 2.35 J/(g.k)

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Homework Answers

Answer #1

Apply heat equation...

boiling point of diethyl ether = 34.6°C

therefore

expect change of phase from 53°C --> 34.6°C change, then 34.6°C to 10°C

note that this:

We require 2 type of heat, latent heat and sensible heat

Sensible heat (CP): heat change due to Temperature difference

Latent heat (LH): Heat involved in changing phases (no change of T)

Then

Q1 = mvapor * Cpvapor * (Tboiling - Tinitial)

Q2 = mvapor * Latent heat of condensation

Q3 = mvapor * Cpliquid * (Tfinal - Tboiling)

substitute

Q1 = 120* 3.74* (34.6- 53) = -8257.92

Q2 = 120* (-26.02*10^3) / 74.12 = -42126.28

Q3 = 120* 2.35* (10- 34.6) = -6937.2

Qtotal = q1+q2+q3 = -(8257.92 +42126.28+6937.2) = -57321.4 J

heat released = 57321.4 J = 57.321 kJ

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