Question

Amount in test tube Absorbance Concentration 1: 100 solution 20 microliters .212A .12A 1:1000 solution 20...

Amount in test tube

Absorbance

Concentration

1: 100 solution

20 microliters

.212A

.12A

1:1000 solution

20 microliters

.344A

.16A

what is the total amount of protein in each fraction? when the inital solution before dilution was .5ml and the standard curve equation is y=.44x, R^2=.08

Homework Answers

Answer #1

Since we have been given the standard curve equation, we will be using it to create the Beer Lambert's equation using analogy as shown below:

A = 0.44*C

Here, C is the conc of the analyte solution in mol/L

For first fraction,

A = 0.212

So,

C = 0.212/0.44 = 0.482 M

Since this is a 1:100 solution, this means that it is diluted 100 times.

So, original solution conc. = 48.2 M

Similarly for second fraction we have:

A = 0.344

So,

C = 0.344/0.44 = 0.782 M

Since this is a 1:1000 solution, this means that it is diluted 100 times.

So, original solution conc. = 782 M

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