Question

255 ml of a 0.15 M MgCl2 (aq) solution is mixed with 125 ml of a 0.50 M NaCl(aq) solution. Determine the molarity of chloride ions in the resulting solution.

Answer 1

Concentration of mixture = (n1*C1*V1+ n2*C2*V2) / (V1+V2)

where C1 --> Concentration of 1 component

V1-->volume of 1 component

C2 --> Concentration of other component

V2-->volume of other component

n1 --> number of particle from 1 molecule of 1st component

n2 --> number of particle from 1 molecule of 2nd component

we have below equation to be used:

C = (n1*C1*V1+ n2*C2*V2) / (V1+V2)

C = (1*0.15*255+2*0.5*125)/(255+125)

C = 0.43 M

Answer: 0.43 M