Question

Calculate each of the following quantities in 2.40 moles H₃PO₄

moles of H =
moles of O =

atoms of P=

atoms of O

Answer 1

Sol :- As, 1 mole of molecule = Atomicity of the atom in molecule x 6.022 x 10²³ atoms

So,

(a). 1 mole of H₃PO₄ contains = 3 moles of H

So,

2.40 moles of H₃PO₄ contains = 2.40 x 3 moles of H

= 7.2 moles of H

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(b). 1 mole of H₃PO₄ contains = 4 moles of O

So,

2.40 moles of H₃PO₄ contains = 2.40 x 4 moles of O

= 9.6 moles of O

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(c). 1 mole of H₃PO₄ contains = 1 x 6.022 x 10²³ atoms of P

So,

2.40 moles of H₃PO₄ contains = 2.40 x 1 x 6.022 x 10²³ atoms of P

= 1.45 x 10²⁴ atoms of P

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d). 1 mole of H₃PO₄ contains = 4 x 6.022 x 10²³ atoms of O

So,

2.40 moles of H₃PO₄ contains = 4 x 2.40 x 6.022 x 10²³ atoms of O

= 5.78 x 10²⁴ atoms of O