1) Iron (III) oxide is Fe2O3 , O has 15.999 amu , Fe has atomic mass of 55.845 amu
Fe2O3 molar mass = ( 2 x Fe atomic mass) + ( 3 x O atomic mass)
= ( 2 x 55.845 amu) + ( 3 x 15.999 amu)
= 159.7 amu
2) C18H27NO3 molar mass = ( 18 x C atomic mass) + ( 27 x H atomic mass) + N atomic mass +
(3 xO atomic mass)
= ( 18 x 12.01 amu) + ( 27 x 1.008 amu) + ( 14 amu) + ( 3 x 15.999 amu)
= 305.4 amu
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