1) This is voltaic cell Pt (s) | Pt2+ (aq, 5.0 M) || Au+ (aq, 2.0 × 10–5 M) | Au (s) How do I get cell potential of this voltaic cell at 25°C?
These are the answer options : 0.360V, 0.640 V, 0.490V, 0.191V, 0.330V
2) What final concentration of NH3 is needed to lower Cu2+ to 6.4*10^-14M that was 1.43*10^4M in Cu^2+(aq)? (volume stays same even NH3 gas is going through the solution) (Kf of [Cu(NH3)4] 2+ = 5 × 10^12)
Possible answer options: 0.0725M, 0.0771 M, 0.109M, 0.145M, 0.307M
Get Answers For Free
Most questions answered within 1 hours.